Go Math Grade 3 Chapter 2 Test Review Pdf

Students of quaternary grade tin collect chapter three Multiply ii-Digit Numbers Go Math Homework Review/Test Answer key from this page in pdf format. All you have to do is click on the links provided over here and exercise more from the HMH Become Math Grade 4 Answer Primal Homework FL Affiliate iii Multiply 2-Digit Numbers Review/Exam. All the same, students can score practiced marks in the exam.

Go Math Grade 4 Respond Central Homework FL Chapter 3 Multiply 2-Digit Numbers Review/Test

Moreover, educators and instructors tin can also make use of this Go Math Course 4 Answer Key Homework FL Review/Test as a exam paper to keep the exam and verify their student'due south knowledge. Nosotros equally a squad designed this guide by providing detailed solutions for each and every question from Exercise Tests, Chapter Tests, Cumulative Practice. Do regularly by using the 4th Grade Become Math Chapter three Respond Key Review/Examination and besides employ it as a quick reference to assess your knowledge subsequently preparing the concepts inside it.

Chapter 3: Review/Test

• Review/Exam – Page No. 131
• Review/Examination – Page No. 132
• Review/Test – Folio No. 133
• Review/Examination – Folio No. 134

Review/Examination – Page No. 131

Concepts and Skills

Question ane.
Explain how to find 14 × 19 by breaking apart the factors into tens and ones and finding the sum of the four partial products.

Reply: 266.

Explanation:
We can break 14 and nineteen every bit ten+iv and 10+nine and to get the answer we will multiply both of the get-go two numbers past the other 2. So we will multiply 10(10+9) and 4(10+9), then the values volition exist (100+ninety) and (xl+36). By adding both nosotros will get 100+ninety+twoscore+36= 266

Question 2.
Explain how to discover 40 × 80 using mental math.

Reply: 3600.

Explanation:
Past using mental math we will multiply 4×viii= 36 then nosotros volition add zeros, then the respond will be 3600.

Gauge the product. Choose a method.

Question three.
eighty × 26

Answer: two,080.

Explanation:
80
×26
———
480
+160
———–
2,080

Question 4.
xix × $67
$ ____

Answer: $one,273.

Explanation:
By breaking apart the factors into tens and ones and we tin find the sum of the four fractional products.
nineteen×67= (x+9)×(60+7)
= (10×60)+(10×7)+(nine×60)+(9×vii)
= 600+70+540+63
= $1,273.

Question 5.
43 × 25

Respond: 1,075.

Explanation:
By breaking autonomously the factors into tens and ones and we can find the sum of the four partial products.
43 × 25= (40+three)×(20+5)
= (40×20)+(40×5)+(3×twenty)+(3×5)
= 800+200+60+15
= one,075.

Question six.
54 × 83

Answer: 4,482.

Explanation:
By breaking autonomously the factors into tens and ones and we can observe the sum of the 4 fractional products.
54 × 83= (l+4)×(80+3)
= (l×lxxx)+(l×3)+(iv×80)+(four×3)
= 4000+150+320+12
= 4,482.

Estimate. Then find the production.

Question vii.
$ 2 four
× nine 6
———–
Approximate: $ ________
Production: $ _________

Answer:
Judge: $ 2,300
Product: $ 2,304

Explanation:
$ 2 4
× 9 6
———–
14 iv
+ 216
———–
2,304

Question eight.
4 4
× 6 0
————
Estimate: _________
Product: _________

Answer:
Gauge: 2,600.
Product: two,640.

Explanation:
4 4
× 6 0
————
00
+264
———–
2640

Question nine.
ix 9
× 1 iv
————
Judge: _________
Production: _________

Answer:
Guess: i,400
Product: i,386

Explanation:
nine ix
× 1 4
————
396
+99
———–
1,386.

Question 10.
6 7
× ii 5
————
Estimate: _________
Production: _________

Answer:
Estimate: one,700
Production: 1,675

Explanation:
vi seven
× 2 v
————
335
+134
————
one,675

Question 11.
iii 6
× five vii
————
Estimate: _________
Product: _________

Answer:
Guess: two,000.
Product: ii,052.

Caption:
3 half-dozen
× 5 vii
————
252
+180
———–
ii,052

Question 12.
$ five iv
× two nine
————
Estimate: $ _________
Product: $ _________

Answer:
Gauge: 1,600.
Production: i,566.

Caption:
$ v 4
× 2 9
————
486
+108
———–
1,566

Question 13.
vii half dozen
× 3 8
————
Guess: _________
Production: _________

Answer:
Estimate: two,900.
Product: ii,888.

Explanation:
seven 6
× 3 eight
————
608
+228
———–
2,888.

Question xiv.
8 5
× 4 half-dozen
————
Guess: _________
Product: _________

Reply:
Estimate: 3,900.
Product: 3,910

Explanation:
8 5
× 4 half-dozen
————
510
+340
———-
3,910.

Review/Test – Page No. 132

Fill in the bubble completely to show your respond.

Question 15.
Each month Sid's parents put $75 into his college fund. How much do his parents put in the fund during two years?
Options:
a. $150
b. $450
c. $ane,800
d. $xv,300

Reply: c.

Explanation:
As Sid's parents put $75 into his college fund, during two years Sid's parent'south fund $75×24= $1800.

Question 16.
Mrs. Jenks wrote the right respond to a homework problem on the lath below. Which of the following could have been the homework trouble?

Options:
a. 5 × 4,000
b. 50 × 400
c. fifty × 40
d. 50 × iv,000

Answer: c.

Caption:
Mrs. Jenks's homework problem is 50 × xl because l × xl= 2,000.

Question 17.
George buys 30 cartons of 18 eggs for the Community Pancake Breakfast. How many eggs does he purchase?
Options:
a. 340
b. 354
c. 460
d. 540

Reply: d

Caption:
As George bought 30 cartons of xviii eggs for the Community Pancake Breakfast, the number of eggs George bought is xxx×18= 540.

Review/Exam – Page No. 133

Fill up in the bubble completely to show your answer.

Question 18.
Mrs. Sampson donated a carton of pencils for each of the 35 classes at Lancet Elementary Schoolhouse. Each carton holds 64 pencils. Which is the best estimate for the number of pencils Mrs. Sampson donated?
Options:
a. A 99
b. B 1,800
c. C ii,400
d. D ii,800

Answer:  c.

Explanation:
As Mrs. Sampson donated a carton of pencils for each of the 35 classes at Lancet Unproblematic Schoolhouse, and each carton holds 64 pencils, and then Mrs. Sampson donates 35×64= two,240. And the estimated value is 2,400.

Question 19.
The school's athletic department ordered 95 dozen badminton feather shuttles. How many plumage shuttles were ordered?
Options:
a. A two,280
b. B one,140
c. C 1,030
d. D 114

Answer: b

Explanation:
Ane dozen is equal to 12. Equally schoolhouse's athletic section ordered 95 dozen badminton feather shuttles, and then 95 dozens ways
95×12= one,140 badminton feather shuttles.

Question 20.
Jill sold 35 adult tickets and 48 child tickets for a fund-raising dinner. An adult ticket costs $18 and a child ticket costs $14. How much did Jill collect for the tickets?
Options:
a. A $one,354
b. B $ane,302
c. C $ane,232
d. D $1,102

Answer: b

Explanation:
As Jill sold 35 adult tickets and 48 child tickets for a fund-raising dinner and each adult ticket costs $18 and a kid ticket costs $fourteen, so total amount Jill collected is 35×$18= 630 and 48×$18= 672 by calculation 630+672= $1,302.

Question 21.
Which shows a fashion to find 35 × 74?
Options:
a. A (30 × 7) + (30 × 4) + (70 × 3) + (70 × 5)
b. B (xxx × 70) + (30 × iv) + (50 × 70) + (fifty × 4)
c. C (xxx + 70) + (30 + 4) + (70 + 30) + (70 + 5)
d. D (thirty × 70) + (30 × 4) + (v × 70) + (5 × 4)

Answer: d

Caption:
By breaking apart the factors into tens and ones and finding the sum of the four partial products,
35 × 74= (30 × 70) + (30 × iv) + (five × 70) + (five × 4)

Question 22.
New seats are beingness delivered to the theater. In that location are 45 new seats for each row in a fifteen-row section. How many seats are being delivered?
Options:
a. A 60
b. B 400
c. C 675
d. D 1,000

Answer: c

Caption:
As new seats are beingness delivered to the theater and there are 45 new seats for each row in a fifteen-row section, so the full number of new seats is 45×15= 675.

Review/Test – Folio No. 134

Synthetic Response

Question 23.
Gulfside Gifts has 48 boxes of postcards to sell. There are 24 postcards in each box. If the store sells three boxes of postcards, how many postcards does the shop have left to sell? Explicate how y'all found the respond.
______ remaining cards

Answer: ane,080 remaining cards.

Explanation:
As Gulfside Gifts has 48 boxes of postcards to sell and at that place are 24 postcards in each box. Then full number of mail cards are
48×24= one,152. And the shop sold iii boxes of postcards i.e 3×24= 72, and so shop has left one,152-72= 1,080 cards are remaining to sell.

Question 24.
Several steps in finding the production of 68 and 34 are shown below. Depict the remaining steps. Use pictures, words, or numbers. Then consummate the multiplication.

_____

Reply:  2,312.

Caption:
68
× 34
———-
272
+ 204
———
2,312

Operation Task

Question 25.
A urban center is having a festival in a local park. Alison'due south Bakery has agreed to donate $1,200 worth of baked goods for the event. The metropolis wants to gild 12 loaves of holiday bread, 18 dozen biscuits, 12 dozen bagels, and 14 dozen multigrain rolls.
A. Is the cost of the broiled goods under the $1,200 donation limit? Use pictures, numbers, or words to explicate how you lot found your answer.

Respond: Yes, the donation is under $1,200.

Caption:
As the city ordered 12 loaves of holiday breadstuff, 18 dozen biscuits, 12 dozen bagels, and 14 dozen multigrain rolls. And holiday bread costs $20, one dozen busicuits costs $12, and 1 dozen bagels costs $28, ane dozen multigrain rolls costs $22. So by adding them
(12×20)+(12×18)+(12×28)+(14×22) we will get $ane,100 which is less than $ane,200

Question 25.
B. If yes, what could the city add to the order? If no, what could the city remove from the order?

Answer: The city tin add whatever they desire with the remaining $100. Equally $i,200-$1,100= $100.

Determination:

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